Answer:
[tex]thermal conductivity k = 0,17045 \frac{W }{m * °C}[/tex]
It is probably made of wood
Explanation:
The heat transmission for the wall is:
[tex]Q = \frac{k * A * dT}{e}[/tex]
Where k is the conductivity, A the area, dT the thermal gradient, and e the thickness.
Solving for k:
[tex]k = \frac{Q * e}{A * dT}[/tex]
replacing:
[tex]A = 4m * 6m = 24 m2[/tex]
[tex]e = 0,1 m[/tex]
[tex]Q = 900 W[/tex]
[tex]dT = 30 - 8 = 22 °C[/tex]
[tex]k = 0,17045 \frac{W }{m * °C}[/tex]
The wood has conductivity values between 0,14 and 0,22 w/m°C