Question

What is the nth term of the geometric sequence that has a common ratio of 6 and 24 as its third term?

Answer 1

an=a1(r)^(n-1) is it

common ratio is r
24 is 3rd term
a3=a1(6)^(3-1)=24
a1(6)^2=24
a1(36)=24
divide boh sides by 36
a1=2/3

therefor
$a_{n}=a_{1}(6)^{n-1}$