Answer:
62.5%
Explanation:
We are given that
A ten-station transfer machine has ideal cycle time=30 sec=[tex]\frac{30}{60}=0.5 min[/tex]
Frequency of line=0.075 stops per cycle
Average time=4 min
We have to determine the line efficiency
[tex]T_p=0.5+0.075(4)=0.5+0.3=0.8[/tex]
Line efficiency=[tex]\frac{0.5}{0.8}\times 100=[/tex]62.5%
Hence, the line efficiency=62.5%