Question

What is the value of t?

t−12
2

=
3t
2

−3



A –3

B –1

C 1

D 3

Answer 1

Answer:

A) t = -3

Step-by-step explanation:

We have the expression $\frac{(t-12)}{2}=\frac{3t}{2}-3$ and we have to find the value of t.

First we are going to reorder the expression:

$\frac{(t-12)}{2}=\frac{3t}{2}-3\\\\3=\frac{3t}{2}-\frac{(t-12)}{2}\\\\3=\frac{3t-t-(-12)}{2}\\\\3=\frac{2t+12}{2}$

Now we have to multiply each side by 2,

$3=\frac{2t+12}{2}\\\\3.2=\frac{2t+12}{2}.2\\\\6=2t+12$

Subtract (-12) in both sides,

$6=2t+12\\6-12=2t+12-12\\-6=2t$

Divide both sides in 2,

$-6=2t\\\frac{-6}{2} =\frac{2t}{2} \\-3=t$

The answer is option A) t = -3.