Question

A balloon is filled with 35.0 L of helium in the morning when the temperature is 303 degrees kelvin. By 3:00 p.m., the temperature has risen to 333 degrees kelvin. What is the new volume of the balloon?

2882 L

38.5 L

31.8 L

65.0 L

Answer 1

Answer:

38.5 L

Explanation:

For this question, we can use

V1/T1=V2/T2

where

V1 (initial volume)= 35 L

T1 (initial temperature in Kelvin)= 303 K

V2(final volume)= ?

T2 (final temperature in Kelvin)= 333K

Since we are trying to find the final volume, we can rearrange the equation to say

V2= (V1/T1) × T2

V2= (35/303)×333

V2= 38.5 L