Respuesta :
Answer:
The measure of the largest angle is 120°
Step-by-step explanation:
Lets explain how to find the measure of an angle from the length of the
sides of the triangle
- We can do that by using the cosine rule
- If the three angles of the triangle are A , B , C, then the side opposite
to angle A is BC , the side opposite to angle B is AC and the side
opposite to angle C is AB, So to find measure of angle A use the rule
[tex]cos(A)=\frac{(AB)^{2}+(AC)^{2}-(BC)^{2}}{2(AB)(AC)}[/tex]
Lets solve the problem
- Assume that the triangle is ABC where AB = 14 cm , BC = 10 cm and
AC = 6 cm
- We need to find the measure of the largest angle
- The largest angle is opposite to the longest side
∵ The longest side is AB
∴ The largest angle is C
By using the rule above
∴ [tex]cos(C)=\frac{(AC)^{2}+(BC)^{2}-(AB)^{2}}{2(AC)(BC)}[/tex]
∵ AB = 14 cm , BC = 10 cm , AC = 6 cm
∴ [tex]cos(C)=\frac{(6)^{2}+(10)^{2}-(14)^{2}}{2(6)(10)}[/tex]
∴ [tex]cos(C)=\frac{36+100-196}{120}[/tex]
∴ [tex]cos(C)=\frac{-60}{120}=-0.5[/tex]
∴ cos(C) = -0.5 ⇒ that means angle C is obtuse angle
∴ m∠C = [tex]cos^{-1}(-0.5)=120[/tex]
* The measure of the largest angle is 120°
Hello!
A triangle has sides measuring 14 cm, 10 cm and 6 cm. The measure of the largest angle of this triangle measures:
Note: Perimeter = 30
We have the following data:
p (perimeter) = 14 + 10 + 6 = 30
a = 14 cm
b = 10 cm
c = 6 cm
α (angle) = ?
*** Note: The largest angle (α) is always opposite the larger side.
We apply the data to the Cosine Law, let's see:
[tex]a^2 = b^2 + c^2 - 2*b*c*cos\:\alpha[/tex]
[tex]14^2 = 10^2 + 6^2 - 2*10*6*cos\:\alpha[/tex]
[tex]196 = 100 + 36 - 120\:cos\:\alpha[/tex]
[tex]120\:cos\:\alpha = -196 + 100 + 36[/tex]
[tex]120\:cos\:\alpha = -60[/tex]
[tex]cos\:\alpha = \dfrac{-6\diagup\!\!\!\!0}{12\diagup\!\!\!\!0} \frac{\div6}{\div6}[/tex]
[tex]cos\:\alpha = \dfrac{-1}{2}[/tex]
[tex]\boxed{\boxed{cos\:\alpha = 120\º}}\:\:\:\:\:\:\bf\purple{\checkmark}[/tex]
Answer:
The measure of the largest angle of the triangle is 120º
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