Answer:
[tex]g_{planet} = \frac{3}{2}g[/tex]
Explanation:
As we know that the acceleration due to gravity is given as
[tex]g = \frac{GM}{R^2}[/tex]
now we know that mass is the product of density and volume
so we will have
[tex]M = \rho \times \frac{4}{3}\pi R^3[/tex]
Now we have
[tex]g = \frac{G(\rho \frac{4}{3}\pi R^3)}{R^2}[/tex]
[tex]g = \frac{4}{3}\rho \pi R G[/tex]
now size of new planet is half that of size of Earth and the density is 3 times the density of Earth
so we have
[tex]g_{planet} = \frac{4}{3}(3\rho)\pi (\frac{R}{2}) G[/tex]
[tex]g_{planet} = \frac{3}{2}g[/tex]