Question

What is the density, in Mg/m3, of a substance with a density of 0.14 lb/in3? (3 pts) What is the velocity, in m/sec, of a vehicle traveling 70 mi/hr?

Answer 1

Answer:

$276.74\times 10^8Mg/m^3$

31.29 m/sec

Explanation:

We have given density of substance $0.14lb/in^3$

We have convert this into $Mg/m^3$

We know that 1 lb = 0.4535 kg. so 0.14 lb = 0.14×0.4535 = 0.06349 kg

We know that 1 kg = 1000 g ( 1000 gram )

So 0.06349 kg = 63.49 gram

And we know that 1 gram = 1000 milligram

So 63.49 gram $=63.49\times 10^3\ Mg$

We know that $1 in^3=1.6387\times 10^{-5}m^3$

So $0.14in^3=0.14\times 1.6387\times 10^{-5}=0.2294\times 10^{-5}m^3$

So $0.14lb/in^3$ =\frac{63.49\times 10^3}{0.2249\times 10^{-5}}=276.74\times 10^8lb/m^3[/tex]

In second part we have to convert 70 mi/hr to m/sec

We know that 1 mi = 1609.34 meter

So 70 mi = 70×1609.34 = 112653.8 meter

1 hour = 3600 sec

So 70 mi/hr $=\frac{70\times 1609.34meter}{3600sec}=31.29m/sec$