Answer:
J(2, 5 )
Step-by-step explanation:
Using the section formula
[tex]x_{J}[/tex] = [tex]\frac{1(-2)+2(4)}{2+1}[/tex] = [tex]\frac{-2+8}{3}[/tex] = [tex]\frac{6}{3}[/tex] = 2
[tex]y_{J}[/tex] = [tex]\frac{1(1)+2(7)}{2+1}[/tex] = [tex]\frac{1+14}{3}[/tex] = [tex]\frac{15}{3}[/tex] = 5
Thus J = (2, 5 )
