Answer:
460 Hz
Explanation:
the given resonating frequency of the device
f₁ = 920 Hz and f₂ = 1380 Hz
fundamental frequency of the device is
f₀ = n₂ - n₁
= 1380 - 920
= 460 Hz
expression of frequency of organic pipe open at both ends
[tex]f_0=n\dfrac{\nu}{2l}[/tex]
at n = 1
[tex]f_0=\dfrac{\nu}{2l} = 460 Hz[/tex]
the frequency ratios of the closed pipe
[tex]f_0:f_1:f_2: ...... =[1:2:3:.........]f_0[/tex]
=[1:2:3:.........]460 Hz
= 460 Hz : 920 Hz : 1380 Hz
so, the lowest frequency for the pipe open at both end is 460 Hz