Answer:
[tex]K_e_q=22.75878093\frac{N}{m}[/tex]
[tex]f=1.363684118Hz[/tex]
Explanation:
In order to calculate the equivalent spring constant we need to use the next formula:
[tex]\frac{1}{K_e_q} =\frac{1}{K_1} +\frac{1}{K_2} +\frac{1}{K_3} +\frac{1}{K_4}[/tex]
Replacing the data provided:
[tex]\frac{1}{K_e_q} =\frac{1}{113} +\frac{1}{65} +\frac{1}{102} +\frac{1}{101}[/tex]
[tex]K_e_q=22.75878093\frac{N}{m}[/tex]
Finally, to calculate the frequency of oscillation we use this:
[tex]f=\frac{1}{2(pi)} \sqrt{\frac{k}{m} }[/tex]
Replacing m and k:
[tex]f=\frac{1}{2(pi)} \sqrt{\frac{22.75878093}{0.31} } =1.363684118Hz[/tex]