Question

A special standard weight, known to weight 10 N to high accuracy, is used to check the accuracy of two spring scales. On the first scale the weight gives a reading of 8.4 N. On the second scale the weight gives a reading of 9.1 N. The percent difference between the measurements of the two scales is %. (Never negative.)

Answer 1

Answer:

16 % and 9 %

Explanation:

Accurate reading = 10 N

reading of first balance = 8.4 N

reading of second balance = 9.1 N

Percentage difference in first reading

= $\frac{True reading - reading of first balance}{True reading}\times 100 %$

= $\frac{10-8.4}{10}\times 100 %$ = 16 %

Percentage difference in second reading

= $\frac{True reading - reading of second balance}{True reading}\times 100 %$

= $\frac{10-9.1}{10}\times 100 %$ = 9 %