Question

Two moles of He gas are at 25 degrees C and a pressure of 210 kPa. If the gas is heated to 48 degrees C and its pressure reduced to 37 % of its initial value, what is the new volume?

Answer 1

Answer:$0.0686 m^3$

Explanation:

Given

No of moles=2

$T=25^{\circ}\approx 298 K$

$P_1=210 KPa$

$T_2=48 ^{\circ}\approx 321 k$

$P_2=77.7 KPa$

PV=nRT

Substitute

$77.7\times V_2=2\times 8.314\times 321$

$V_2=0.0686 m^3$