Question

A particle of mass m locates at y=d, and another particle of mass 2m locates al y = 3d. What is the center of mass you. ) A YCM = 7d/3 B. You = 20 C. You = 40/3 D. Yo = 4d

Answer 1

Answer:

c.m=(1/∑mi)*∑mi*yi

$c.m.=\frac{m*d+2m*3d}{m+2m}=7d/3$

Explanation:

We solve this problem, with the equation for the center of mass:

c.m=(1/∑mi)*∑mi*yi

$m_i:$   represent the different mass of the system

$y_i:$    represent the position of the different mass of the system

c.m=(1/∑mi)*∑mi*yi=(1/(m+2m))*(m*d+2m*3d)=7d/3