Answer:
given,
speed of red train = 72 km/h = 72× 0.278 = 20 m/s
speed of green train = 144 km/h = 144 × 0.278 = 40 m/s
deceleration of both the train = 1 m/s²
distance between the train when they start decelerating = 950 m
using equation of motion
v² = u² + 2 a s
distance taken by the red train to stop
v² = u² + 2 a s
0 = 20² - 2×1×s
s = 200 m
distance taken by the blue train to stop
v² = u² + 2 a s
0 = 40² - 2×1×s
s = 800 m
so, both train will be cover 200 + 800 = 1000 m
hence, there will be collision between both the trains.
distance traveled by the green train will be 750 m
distance traveled by the red train will be 200 m
so, velocity of the red train will be zero
velocity of the green train will be
v² = u² + 2 a s
v² = 40² - 2 × 1× 750
v = 10 m/s
hence, velocity of the green train will be 10 m/s.