Question

A boy in a sleigh glides on a 40 angle snow-covered hill. The coefficient of kinetic friction between the surface and the sled is 0.12. The acceleration of the sled is: a. 3.6 m / s^2
b. 0.76 m / s^2
c. 2.3 m / s^2
d. 5.4 m / s^2

Answer 1

Answer:

option D

Explanation:

given,

angle of the snow-covering hill (θ) = 40°

coefficient of kinetic friction = 0.12

acceleration of the shed = ?

we know,

F = m a...................(1)

now,

$F = m g sin\theta -\mu_k N sin\theta$.......(2)

comparing  equation (1) with (2)

$m a =m g sin\theta -\mu_k m g sin\theta$

$a = g sin \theta - \mu_k sin\theta$

$a = 9.8\times sin 40^0 - 0.12\times 9.8\times  sin40^0$

a = 5.54 m/s²

Hence, the correct answer is option D