Answer: 50.14 s
Explanation:
We can solve this problem by the following equation:
[tex]V=V_{o}+at[/tex] (1)
Where:
[tex]V=1100\frac{km}{h} \frac{1000 m}{1 km} \frac{1 h}{3600 s}=305.55 m/s[/tex] is the final velocity of the aircraft.
[tex]V_{o}=600\frac{km}{h} \frac{1000 m}{1 km} \frac{1 h}{3600 s}=166.66 m/s[/tex] is the initial velocity of the aircraft
[tex]a=2.77 m/s^{2}[/tex] is the acceleration of the aircraft (taking into account 10 km/h=2.77 m/s and acceleration is \frac{2.77 m/s}{1 s})
[tex]t[/tex] is the time it takes to the aircraft to reach the sound barrier
Isolating [tex]t[/tex] from (1):
[tex]t=\frac{V-V_{o}}{a}[/tex] (2)
[tex]t=\frac{305.55 m/s-166.66 m/s}{2.77 m/s^{2}}[/tex] (3)
Finally:
[tex]t=50.14 s[/tex] (4)