Question

A ball is thrown straight up and reaches a maximum height of 36 m above the point from which it was thrown. With what speed was the ball thrown?

Answer 1

Answer:

Ball is thrown with a velocity of 26.5631 m/sec      

Explanation:

We have given maximum height of the ball h = 36 m

At maximum height velocity will be zero so final velocity v = 0 m/sec

We have to find the velocity through ball is thrown means initial velocity u

As ball is thrown upward and acceleration due to gravity is downward means its opposes the motion

So $g=-9.8m/sec^2$

From third equation of motion we know that $v^2=u^2+2gh$

$0^2=u^2-2\times 9.8\times 36$

$u^2=705.6$

u = 26.5631 m/sec

So ball is thrown with a velocity of 26.5631 m/sec