Answer:
10.29 cm/s
Explanation:
Discharge in to the bowl = 17.0 cm³/s
Diameter of the bowl, d₁ = 1.45 cm
Now,
Rate at which water level rise at its diameter = [tex]\frac{\textup{Discharge}}{\textup{Area of cross-section}}[/tex]
also,
Area of cross-section = [tex]\frac{\pi}{\textup{4}}\times1.45^2[/tex]
or
Area of cross-section = 1.651 cm²
Therefore,
Rate at which water level rise at its diameter = [tex]\frac{\textup{17}}{\textup{1.651}}[/tex]
or
Rate at which water level rise at its diameter = 10.29 cm/s