Answer:
Step-by-step explanation:
Factoring the difference of two squares is as follows:
[tex]a^{2} - b^{2} = (a + b)(a - b)[/tex]
In the given problem, you know that [tex]9x^{4}[/tex] can be broken down to [tex]3x^{2} * 3x^{2}[/tex], and that [tex]64y^{2}[/tex] can be broken down to [tex]8y * 8y[/tex], so plugging those numbers into the above equation, we get the following:
[tex]9x^{4} - 64y^{2}[/tex]
[tex](3x^{2} + 8y)(3x^{2} - 8y)[/tex]
