Two angles are complementary. The measure of the larger angle is 10 more than 4 times the measure of the smaller angle. Find the measures of both angles.


Can someone please help me?

Respuesta :

Answer:

16 = small

74 = big

Step-by-step explanation:

4x+10 = big angle

x = small angle

4x+10+x = 90

5x+10 = 90

5x = 80

x = 16

4 x 16 + 10 = 74

Avocado out!!!!!!!!!

Answer:

[tex]y=16^{\circ},x=74^{\circ}[/tex]

Step-by-step explanation:

Let complementary angles are x and y.

Let x is larger angle between x and y.

We have to find the measure of both angles x and y.

According to question

[tex]x=4y+10[/tex]

We know that complementary angles :Two angles whose sum is 90 degrees.

[tex]x+y=90^{\circ}[/tex]

[tex]4y+10+y=90[/tex]

[tex]5y=90-10=80[/tex]

[tex]y=\frac{80}{5}=16^{\circ}[/tex]

Substitute the value then we get

[tex]x=4(16)+10=74^{\circ}[/tex]

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