Answer:
35.558 amu
Explanation:
Complete this calculation
[tex] \frac{isotope \times \: abundance}{100} + \frac{isotope \times \: abundance}{100} [/tex]
[tex] \frac{35 \times 75.8}{100} + \frac{37 \times 24.4}{100} = 35.558[/tex]
Therefore the answer is 35.558 amu