Question

Be sure to answer all parts. Calculate the number of g of O, that will react with 9.98 mol of CzHg. Enter your answer in scientific notation. The balanced equation is: C3H2(g) + 502(g) → 3C02(g) + 4H2O(g). * 10 (select) A go,

Answer 1

Answer: The mass of oxygen reacted is $1.60\times 10^{3}g$

Explanation:

We are given:

Moles of propane = 9.98 mol  

For the given chemical equation:

$C_3H_8(g)+5O2(g)\rightarrow 3CO_2(g)+4H_2O(g)$

By Stoichiometry of the reaction:

1 mole of propane reacts with 5 moles of oxygen.

So, 9.98 moles of propane will react with = $\frac{5}{1}\times 9.98=49.9mol$ of oxygen.

To calculate the mass of carbon dioxide, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of oxygen = 49.9 moles  

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation:

$49.9mol=\frac{\text{Mass of oxygen}}{32g/mol}\\\\\text{Mass of oxygen}=(49.9mol\times 32g/mol)=1596.8g=1.60\times 10^{3}g$

Hence, the mass of oxygen reacted is $1.60\times 10^{3}g$