Question

What volume of sample, in mL, would be needed to make 2 mL of a 5-fold dilution? (3 significant figures needed)

Answer 1

Answer:

0.400 mL

Explanation:

Hello, the dilution factor (in folds) is given by:

$folds=\frac{total_{volume}}{sample_{volume}}$

Thus, the sample volume with three significant figures is given by:

$sample_{volume}=\frac{2mL}{5"folds"}=0.400 mL$

Best regards.