Answer:
D) He
Explanation:
For adiabatic change
[tex]PV^\gamma = constant[/tex]
\frac{P_2}{P_1} =(\frac{V_1}{V_2} )^\gamma
[tex]\frac{P_2}{P_1} =(\frac{3}{1} )^\gamma[/tex]
[tex]P_2 = P_1 3^\gamma[/tex]
As the value of \gamma increases, P_2 increases.
\gamma for He is 1.67 and \gamma for O₂ IS 1.4
Naturally The value of P_2 is greater for He. Increase in pressure for He is greater.