Answer:
[tex]468.77 ft[/tex]
Explanation:
Charlotte is driving at [tex]70.4\frac{mi}{h}[/tex]
Then Charlotte's speed is [tex]70.4\frac{mi}{h}[/tex]
The time during she drove at this speed is [tex]t=4.54 s[/tex]
There is an equation that relates distance,speed and time (when speed remaings the same) :
[tex]Speed =\frac{distance}{time}[/tex]
[tex]S=\frac{d}{t}[/tex]
First we need to convert the units
[tex]70.4 \frac{mi}{h} .\frac{1 h}{3600s} .\frac{5280 ft}{1mi} =[/tex]
[tex]\frac{7744}{75} \frac{ft}{s}[/tex]
Then
[tex]\frac{7744}{75} \frac{ft}{s} =\frac{d}{4.54s}[/tex]
[tex]\frac{7744}{75} \frac{ft}{s} .4.54s=d[/tex]
[tex]d=468.77ft[/tex]
We suppose that the aceleration is equal to 0 during t=4.54s