Charlotte is driving at 70.4 mi/h and receives a text message. She looks down at her phone and takes her eyes off the road for 4.54 5. How far has Charlotte traveled in feet during this time? distance:

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Answer:

[tex]468.77 ft[/tex]

Explanation:

Charlotte is driving at [tex]70.4\frac{mi}{h}[/tex]

Then Charlotte's speed is [tex]70.4\frac{mi}{h}[/tex]

The time during she drove at this speed is [tex]t=4.54 s[/tex]

There is an equation that relates distance,speed and time (when speed remaings the same) :

[tex]Speed =\frac{distance}{time}[/tex]

[tex]S=\frac{d}{t}[/tex]

First we need to convert the units

[tex]70.4 \frac{mi}{h} .\frac{1 h}{3600s} .\frac{5280 ft}{1mi} =[/tex]

[tex]\frac{7744}{75} \frac{ft}{s}[/tex]

Then

[tex]\frac{7744}{75} \frac{ft}{s} =\frac{d}{4.54s}[/tex]

[tex]\frac{7744}{75} \frac{ft}{s} .4.54s=d[/tex]

[tex]d=468.77ft[/tex]

We suppose that the aceleration is equal to 0 during t=4.54s

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