Answer:
Explanation:
Hello,
At first, consider the balanced reaction for the combustion of the isooctane:
[tex]C_8H_{18}+\frac{25}{2} O_2-->8CO_2+9H_2O[/tex]
Now, the stoichiometric relationship between the hydrocarbon and the oxygen leads to:
[tex]molO_2=230molC_8H_{18}(\frac{\frac{25}{2}mol O_2 }{1mol C_8H_{18}} )=2875molO_2[/tex]
Best regards.