Question

You are given a protein solution with a concentration of 0.15 mg/ml.

v. Suppose that we want to prepare 100 microliters of 10 micrograms/microliters solution. How much of H2O and protein stock do we need to add to obtain the target concentration and volume? (THE CONCENTRATION IS NOT GREATER IN THE QUESTION, YOU NEED TO CONVERT IT TO MICROGRAMS/MICROLITERS.... THEN IT SHOULD MAKE SENSE)

Answer 1

Answer:

6,666.66 micro liter of water and protein stock we will need to add to obtain the target concentration and volume.

Explanation:

Concentration of given solution$C_1 = 0.15 mg/mL$

1 mL = 1000 μL , 1 mg = 1000 μg

$C_1=0.15 mg/mL=\frac{0.15\times 1000 \mu g}{1\times 1000 \mu L}=0.15 \mu g/\mu L$

The volume of the given solution =$V_1= V$

Concentration of required solution = $C_2=10 \mu g/\mu L$

Volume of required solution = $V_2=100 \mu L$

$C_1V_1=C_2V_2$

$V=\frac{C_2V_2}{C_1}=\frac{10 \mu g/\mu L\times 100 \mu L}{0.15 \mu g/\mu L}=6,666.66 \mu L$

6,666.66 micro liter of water and protein stock we will need to add to obtain the target concentration and volume.