Question

High‑speed ultracentrifuges are useful devices to sediment materials quickly or to separate materials. An ultracentrifuge spins a small tube in a circle of radius 13.1 cm at 50000.0 rev/min. What is the centripetal force experienced by a sample that has a mass of 0.00310 kg?

Answer 1

Answer:

Fc = 7.14N

Explanation:

First of all, let's convert everything to the same unit system:

m = 0.0031kg     R = 13.1cm * 1m / 100cm = 0.131m      

ω = 50000 rev/min * 1rev /( 2π rad ) * 1min / 60s = 132.63 rad/s

Now we can calculate centripetal force as:

$Fc = m * \frac{V^2}{R} = m * \frac{(\omega*R)^2}{R}=m*R*\omega ^2$

Replacing the values we get the answer:

Fc = 7.14N

Answer 2

The force needed to move a body in a curved way is understood as centripetal force. The centripetal force experienced by a sample will be 7.14 N.    

What is centripetal force?  

The force needed to move a body in a curved way is understood as centripetal force. This is a force that can be sensed from both the fixed frame and the spinning body's frame of concern.

The direction of centripetal force is always in the path of the center of the course.

The given data in the problem;

r is the radius =13.1 cm=0.13 m

n is the rpm = 50000.0 rev/min  

To find velocity first we have to go to angular velocity

$\omega = \frac{2\pi n}{60} \\\\ \omega = \frac{2\times3.14\times50000}{60} \\\\\omega = 132.63\; rad/sec.$

The centripetal force is given as

$\rm F_C= m\omega^{2} r\\\\F_C= 0.00310(132.63)^2 \times 0.131\\\\\rm{F_C=7.14 N$

Hence The centripetal force experienced by a sample will be 7.14 N.    

To learn more about the centripetal force refer to the link;

https://brainly.com/question/10596517