Question

In the laboratory you are asked to make a 0.575 m nickel(II) acetate solution using 19.9 grams of nickel(II) acetate.

Answer 1

Answer: The volume of solution is 195.8 mL

Explanation:

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.575 M

Given mass of nickel (II) acetate = 19.9 g

Molar mass of nickel (II) acetate = 176.8 g/mol

Putting values in above equation, we get:

$0.575M=\frac{19.9g\times 1000}{176.8g/mol\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{19.9\times 1000}{176.8\times 0.575}=195.8mL$

To prepare 0.575 molar nickel (II) acetate solution, we need to add 19.9 grams of nickel (II) acetate to 195.8 mL of solution.

Hence, the volume of solution is 195.8 mL