Respuesta :
Answer:
a) F = 84.64N
b) The force has to increase.
Explanation:
First of all, let's convert everything to the same unit system:
Vo = 0 m/s Vf = 98 mi/h * 1609.34 m / 1mi * 1h / 3600s = 43.8m/s
d = 1.7m m = 0.15kg
We can calculate force as:
F = m*a where a is the acceleration experiencd by the ball and m is its mass.
In order to calculate acceleration, we can use this formula:
[tex]Vf^2 = V^2 +s*a*d[/tex] Solving for a:
[tex]a = \frac{Vf^2-Vo^2}{2*d} = 564.25m/s^2[/tex]
Now, the force will be:
F = m * a = 84.6N
As we can see in that previous equation, the force is directly proportional to the mass of the ball, so, assuming the final speed of the ball is the same as before (that is, the acceleration is the same), the force will increase in the same proportion as the mass does.
a) The average force exerted on the ball during the pitch F = 84.64N
b)If the mass of the ball has increased the force Will increase
What will be the average force exerted on the wall during the pitch?
First of all, let's convert everything to the same unit system:
Vo = 0 m/s
[tex]V_f =\dfrac{98 \frac{mile}{h} \times 1609.34 }{3600} =43.8 \frac{m}{s}[/tex]
d = 1.7m
m = 0.15kg
The force is from newtons second law
[tex]F= m\times a[/tex]
Now for finding acceleration we have
[tex]V_{f}^2 =V^2+ 2ad[/tex]
[tex]a=\dfrac{V_{f}^2 -V^2}{2d}[/tex]
[tex]a= \dfrac{43.8^2}{1.7} =564.25\dfrac{m}{s^2}[/tex]
Now, the force will be:
[tex]F=m\times a = 0.15\times 564=84.6 N[/tex]
As we can see in that previous equation, the force is directly proportional to the mass of the ball,
so, assuming the final speed of the ball is the same as before (that is, the acceleration is the same)
The force will increase in the same proportion as the mass does.
Thus
a) The average force exerted on the ball during the pitch F = 84.64N
b)If the mass of the ball has increased the force Will increase
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