Question

The volume of a rock is found to be 0.00018 m^3. If the rock's specific gravity is 2.50, what is its weight? (a) 5.41N (b) 3.62 Ib (c) 1.009N (d) 0.991 Ib (e) none of these

Answer 1

Answer:

d)0.991lbf

Explanation:

the property known as specific gravity is the relationship between the density of the fluid and the density of the water, so to find the density of the rock we must multiply the specific gravity by the density of the water = 1000kg / m ^ 3, when we have the density we must multiply it by volume and gravity to find the weight.

W=2.5ρVg

ρ=Density of water=1000kg / m ^ 3

V=0.00018 m^3

g=9.81m/s^2

W=(2.5)(1000)(0.00018)(9.81)

W=4.41N=0.991lbf

Answer 2

The weight should be option A. 5.41N

Calculation of the weight:

Specific gravity refers to the relationship that lies between fluid density and water density.

since the volume of rock is found to be 0.00018 m^3. And, the rock's specific gravity is 2.50

So, here the weight should be

W=(2.5)(1000)(0.00018)(9.81)

W=4.41N

hence, The weight should be option A. 5.41N

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