Answer:
[tex]f(2a-\frac{3}{5})=4a^2+\frac{8a}{5}+\frac{4}{25}[/tex]
Step-by-step explanation:
we have
[tex]f(x)=x^{2} +2x+1[/tex]
Find [tex]f(2a-\frac{3}{5})[/tex]
That means -----> substitute the value of [tex]x=(2a-\frac{3}{5})[/tex] in the function and evaluate
[tex]f(2a-\frac{3}{5})=(2a-\frac{3}{5})^{2} +2(2a-\frac{3}{5})+1[/tex]
[tex]f(2a-\frac{3}{5})=(4a^2-\frac{12a}{5}+\frac{9}{25})+(4a-\frac{6}{5})+1[/tex]
[tex]f(2a-\frac{3}{5})=4a^2+\frac{8a}{5}-\frac{21}{25}+1[/tex]
[tex]f(2a-\frac{3}{5})=4a^2+\frac{8a}{5}+\frac{4}{25}[/tex]
