Answer:
[tex]t=\frac{v_{i}Sin\theta }{g}[/tex]
Explanation:
Let the time taken by the shot to reach to maximum height is t.
initial velocity, vi
angle of projection, θ
Acceleration, g
At maximum height, the vertical component of velocity is zero.
use first equation of motion in vertical motion
[tex]v=u+at[/tex]
[tex]0=v_{i}Sin\theta -gt[/tex]
[tex]t=\frac{v_{i}Sin\theta }{g}[/tex]