Question

An object accelerates from rest to a velocity of 4.0 m/s over a distance of 20 m. What was its acceleration?

Answer 1

Answer: 4/5 m/s

Explanation: To calculate time taken .

Time =distance /velocity =20/4 =5s

Acceleration = 4-0/5 =4/5m/s^2

Answer 2

The acceleration of the object will be "$\frac{4}{5} \ m/s^2$".

The given values are:

Distance,

• d = 20 m

Velocity,

• v = 4.0 m/s

As we know, the formula,

→ $Time (t)= \frac{Distance (d)}{Velocity (v)}$

By substituting the values, we get

→               $= \frac{20}{4}$

→               $= 5 \ s$

hence,

→ Acceleration, $a = \frac{4-0}{5}$

→                            $= \frac{4}{5} \ m/s^2$  

Thus the above answer is right.

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