Question

Which expression and value of six less than the quotient of a number and two increased by ten when n=8

Answer 1

Answer:

The expression is $\frac{n}{2}-6+10$

For n=8 the value of the expression is 8

Step-by-step explanation:

Let

n -----> the number

we know that

"six less than" means we're subtracting 6:

- 6

"The quotient" means division. "Of a number and 2" Usually the numerator is listed first:

n/2

"increased by ten" means we're adding 10:

+10

substitute

$\frac{n}{2}-6+10$

For n=8

substitute the value of n in the expression

$\frac{8}{2}-6+10$

$4-6+10=8$

Answer 2

Answer:

Expression would be $\frac{n}{2}-6+10$

Value would be 8.

Step-by-step explanation:

Here, n represents the unknown number,

∵ The quotient of n and 2 = $\frac{n}{2}$

6 less than  $\frac{n}{2}$ =  $\frac{n}{2}-6$

$\frac{n}{2}-6$ increased by 10 = $\frac{n}{2}-6+10$

Thus, the required expression would be,

$\frac{n}{2}-6+10$

When n = 8,

$\frac{8}{2}-6+10=4-6+10=8$