Answer: 0.9649
Step-by-step explanation:
Let A denote the event that the days are cloudy and B denotes the event that the days are rainy.
Given : For the month of March in a certain city, the probability that days are cloudy :[tex]P(A)=0.57[/tex]
Also in the month of March in the same city,, the probability that the days are cloudy and rainy :[tex]P(A\cap B)=0.55[/tex]
Now by using the conditional probability, the probability that a randomly selected day in March will be rainy if it is cloudy will be :-
[tex]P(B|A)=\dfrac{P(A\cap B)}{P(A)}[/tex]
[tex]\Rightarrow\ P(B|A)=\dfrac{0.55}{0.57}\\\\=0.964912280702\approx0.9649\ \ \text{[Rounded to four decimal places.]}[/tex]
Hence, the probability that a randomly selected day in March will be rainy if it is cloudy = 0.9649