Answer:
Magnitude of boat's acceleration is 1.2 ms⁻²
Explanation:
Given data
Initial velocity = v₁ = 25 m/s
Final velocity = v₂ = 35 m/s
distance = s = 250 m
Acceleration = a = ?
Using 3rd equation of motion
2 a s = v₂² - v₁²
2 × a × (250) = 35² - 25²
500 × a = 600
a = 600/500
a = 1.2 ms⁻²
Thus the acceleration of the boat is 1.2 m/s² until it travel up to 250 m from initial velocity 25m/s to final velocity 35 m/s.