Question

The given line passes through the points (0, ) and (2, 3). On a coordinate plane, a line goes through (0, negative 3) and (2, 3). A point is at (negative 1, negative 1). What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point ()?

Answer 1

Answer:

$y=\frac{x}{5}+\frac{12}{5}$

Step-by-step explanation:

1) The Point-slope form equation is given in this form:

$(x-x_{0})=m(y-y_{0})$

2)Looking at the given graph, we can pick two points: (-5,-4) and (0,-3)

3) Before using the Point-slope form We have to find out the slope:

$m=\frac{-4-(-3)}{0-(-5)} \Rightarrow m=\frac{-4+3}{0+5} \Rightarrow m=\frac{-1}{5}$

4)Parallel lines share the same slope. The one that passes through (-2,2) is found by calculating its linear parameter "b":

$y=\frac{x}{5}+b\Rightarrow 2=\frac{-2}{5}+b\\5*10=(-2+b)*5\Rightarrow 5b=12 \Rightarrow \frac{5b}{5} =\frac{12}{5} \Rightarrow b=\frac{12}{5}$

Then, the answer is:

$y=\frac{x}{5}+\frac{12}{5}$