Respuesta :
Answer:
The two sample means are 10 and 12 with variances of 20 and 25
Step-by-step explanation:
The formula used for t-statistics is:
[tex]t=\frac{\bar{x_{1}}-\bar{x_{2}} }{\sqrt{\frac{s_{1}^2}{n_{1}}+\frac{s_{2}^2}{n_{2}} }}[/tex]
Thus t is inversely proportional to s² i.e. variance.
Hence for larger value of variance, we get small value of t-statistics and vice-versa.
Thus for produce the largest value for an independent-measures t statistic, the two sample means are 10 and 20 with variances of 20 and 25.
Answer:
The two sample means are 10 and 20 with variances of 20 and 25 produce the largest value for an independent-measures t statistic.
Explanation:
Option A : The two sample means are 10 and 20 with variances of 20 and 25.
[tex]s_{M_{1}-M_{2}}=\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}}[/tex]
[tex]=\sqrt{\frac{20}{10}+\frac{25}{10}}[/tex]
[tex]=\sqrt{2+2.5}[/tex]
[tex]=\sqrt{4.5}[/tex]
[tex]=2.12 \\[/tex]
[tex]t=\frac{M_{1}-M_{2}}{s_{M_{1}-M_{2}}}[/tex]
[tex]=\frac{10-20}{2.12}[/tex]
[tex]=\frac{-10}{2.12}[/tex]
[tex]=-4.72[/tex]
The two sample means are 10 and 20 with variances of 20 and 25 produce the largest value for an independent-measures t statistic.
Learn more about sample mean, refer:
https://brainly.com/question/18060320