​Which of the following sets of data would produce the largest value for an independent-measures t statistic? ​The two sample means are 10 and 20 with variances of 20 and 25 ​The two sample means are 10 and 20 with variances of 120 and 125 ​The two sample means are 10 and 12 with sample variances of 20 and 25 ​The two sample means are 10 and 12 with variances of 120 and 125

Respuesta :

Answer:

The two sample means are 10 and 12 with variances of 20 and 25

Step-by-step explanation:    

The formula used for t-statistics is:

     [tex]t=\frac{\bar{x_{1}}-\bar{x_{2}} }{\sqrt{\frac{s_{1}^2}{n_{1}}+\frac{s_{2}^2}{n_{2}}  }}[/tex]

Thus t is inversely proportional to s² i.e. variance.

Hence for larger value of variance, we get small value of t-statistics and vice-versa.

Thus for produce the largest value for an independent-measures t statistic, the two sample means are 10 and 20 with variances of 20 and 25.

Answer:

The two sample means are 10 and 20 with variances of 20 and 25 produce the largest value for an independent-measures t statistic.

Explanation:

Option A : The two sample means are 10 and 20 with variances of 20 and 25.

[tex]s_{M_{1}-M_{2}}=\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}}[/tex]

[tex]=\sqrt{\frac{20}{10}+\frac{25}{10}}[/tex]

[tex]=\sqrt{2+2.5}[/tex]

[tex]=\sqrt{4.5}[/tex]

[tex]=2.12 \\[/tex]

[tex]t=\frac{M_{1}-M_{2}}{s_{M_{1}-M_{2}}}[/tex]

[tex]=\frac{10-20}{2.12}[/tex]

[tex]=\frac{-10}{2.12}[/tex]

[tex]=-4.72[/tex]

The two sample means are 10 and 20 with variances of 20 and 25 produce the largest value for an independent-measures t statistic.

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