Answer:
a) The US power rating for the european bulb must be 27.27 W
b) The current in the United Stated for the european bulb is 0.227A
Explanation:
First of all the bulb is not going to light in 120V like it does in 220V, the bright is going to be much lower (near 1/4). Now, lets take a look on a circuit perspective:
The bulb in a circuit is modeled like a simple resistor, so we have a resistor conected to a voltage source, see figure 1. There we have a current [tex]I_{1}[/tex] given by:
[tex]I_{1}=\frac{V_{1} }{R}[/tex]
Where [tex]V_{1}[/tex] is the 220v Input voltage, R is the resistance from the bulb. In the problem we have the power consumption in watts given by:
[tex]W_{1}= V_{1]*I_{1}[/tex]
Clearing [tex]I_{1}[/tex]
[tex]I_{1} =\frac{I_{1}}{W_{1} } =\frac{100}{220} =0.4545 A[/tex]
Now, from ohm's law
[tex]\frac{V_{1} }{I_{1} } =R=\frac{220 }{0.4545 }=484 ohm[/tex]
So 484 ohm is the resistance from the bulb.
Now in the circuit lets replace the voltage source from 220v to 120v and lets calculate the current, and the power consuptiom
[tex]I_{2}= \frac{V_{2}}{R}=\frac{110}{484} =0.227 A[/tex]
And the power consuptiom:
[tex]W_{2}= V_{2]*I_{2}=110*0.227=27.27Watts[/tex]