Answer:
[tex]\large\boxed{-\dfrac{1}{10}=-0.1}[/tex]
Step-by-step explanation:
[tex]3\dfrac{2}{5}+-3\dfrac{1}{2}\qquad\text{find}\ LCD=(5)(2)=10\\\\=3\dfrac{2\cdot2}{5\cdot2}-3\dfrac{1\cdot5}{2\cdot5}=3\dfrac{4}{10}-3\dfrac{5}{10}=(3-3)+\dfrac{4-5}{10}=-\dfrac{1}{10}[/tex]
