Respuesta :
Answer:
The pulling force that the man should apply to create an upward acceleration of [tex]1.20m/s^{2}[/tex] is [tex]P=621.5N[/tex]
Explanation:
Hi
As it shows in the drawing at the end, we have that the total mass of the man plus the platform is [tex]113 kg[/tex], then the force downward [tex]W[/tex] is [tex]W=mg=113Kg*9.8m/s^{2}=1107.4N[/tex].
Due the man needs to do a pulling force upward capable of lifting himself and the platform with an acceleration of [tex]1.20m/s^{2}[/tex], this force should create an acceleration greater than gravity by [tex]1.20m/s^{2}[/tex]. then [tex]a_{up}=g+1.2m/s^{2}=9.8m/s^{2}+1.2m/s^{2}=11m/s^{2}[/tex]. Therefore the force should be [tex]P_{up}=ma_{up}=113kg*11m/s^{2}=1243N[/tex].
Finally, as we have a pulley arrangement connected to the platform, it gives the man a mechanical advantage, so he has to do only half of that upward force
, therefore [tex]P=\frac{1243N}{2}=621.5N[/tex].
