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What is the slope of the line that passes through the given points?


(2, 12) and (6, 11)

A. –1 over 4
B. 1 over 4
C. 4
D. –4

What is the slope of the line that passes through the given points?

(6, –1) and (–3, –1)

A. undefined
B. 0
C. –two-thirds
D. –start fraction 3 over 2 end fraction

Respuesta :

Answer:

B. 0

A. -¼

Step-by-step explanation:

-y₁ + y₂\-x₁ + x₂ = m

[tex]\frac{-1 + 1}{-6 + 3} = \frac{0}{-3} = 0 \\ \\ \frac{-12 + 11}{-2 + 6} = - \frac{1}{4} [/tex]

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Answer:

For points :  (2, 12) and (6, 11)

, option A. is correct.

For points : (6, –1) and (–3, –1), option B. is correct

Step-by-step explanation:

We are given points in both the questions and we need to find the slope.

Slope refers to steepness of curve .It is basically change in y with change in x.

For two points [tex]P\left ( x_1,y_1 \right )\,,\,Q\left ( x_2,y_2 \right )[/tex], slope of line PQ is [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

For points : (2, 12) and (6, 11)

Let [tex]P\left ( x_1,y_1 \right )=(2, 12)\,,\,Q\left ( x_2,y_2 \right )=(6, 11)[/tex],

Slope is [tex]\frac{11-12}{6-2}=\frac{-1}{4}[/tex] i.e, - 1 over 4

So, option A. is correct.

For points : (6, –1) and (–3, –1)

Let [tex]P\left ( x_1,y_1 \right )=(6, -1)\,,\,Q\left ( x_2,y_2 \right )=(-3, -1)[/tex]

Slope is [tex]\frac{-1+1}{-3-6}=\frac{0}{-9}=0[/tex]

So, option B. is correct

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