Respuesta :
Answer:
B. 0
A. -¼
Step-by-step explanation:
-y₁ + y₂\-x₁ + x₂ = m
[tex]\frac{-1 + 1}{-6 + 3} = \frac{0}{-3} = 0 \\ \\ \frac{-12 + 11}{-2 + 6} = - \frac{1}{4} [/tex]
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Answer:
For points : (2, 12) and (6, 11)
, option A. is correct.
For points : (6, –1) and (–3, –1), option B. is correct
Step-by-step explanation:
We are given points in both the questions and we need to find the slope.
Slope refers to steepness of curve .It is basically change in y with change in x.
For two points [tex]P\left ( x_1,y_1 \right )\,,\,Q\left ( x_2,y_2 \right )[/tex], slope of line PQ is [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
For points : (2, 12) and (6, 11)
Let [tex]P\left ( x_1,y_1 \right )=(2, 12)\,,\,Q\left ( x_2,y_2 \right )=(6, 11)[/tex],
Slope is [tex]\frac{11-12}{6-2}=\frac{-1}{4}[/tex] i.e, - 1 over 4
So, option A. is correct.
For points : (6, –1) and (–3, –1)
Let [tex]P\left ( x_1,y_1 \right )=(6, -1)\,,\,Q\left ( x_2,y_2 \right )=(-3, -1)[/tex]
Slope is [tex]\frac{-1+1}{-3-6}=\frac{0}{-9}=0[/tex]
So, option B. is correct