Answer:
[tex]6y^2\sqrt{10} +6\sqrt{20y}[/tex]
Step-by-step explanation:
First we need to write equation :
[tex]3\sqrt{10}(y^2\sqrt{4} +\sqrt{8y} )=[/tex]
We know that sqrt(4) is 2 .
[tex]3\sqrt{10}(2y^2+2\sqrt{2y} )[/tex]
Multiply :
[tex]6y^2\sqrt{10} +6\sqrt{20y}[/tex]
