Question

A 2,200-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 3.60 m before coming into contact with the top of the beam, and it drives the beam 14.4 cm farther into the ground as it comes to rest. Using energy considerations, calculate the average force the beam exerts on the pile driver while the pile driver is brought to rest. magnitude N direction

Answer 1

Answer:

56.1132 KN

Explanation:

The decrease in the potential energy of the pile driver = Mgh_net

= 2200×9.81( 3.60+ 0.144)= 22×981×3.744= 21,582×3.744=80803.008 J

This decrease in potential energy will be equal to the work done by beam on the pile driver

Work done = force×displacement = F×d

⇒80803.008= F×0.144

⇒$F_{avg}= \frac{80803.088}{0.144}$

=561,132 N

= 56.1132 KN