Respuesta :

For this case we have that by definition of power properties is met:

[tex](a^m)^n=a^{m*n}[/tex]

It is also true that:

[tex]a^{-1}=\frac{1}{a^1}=\frac{1}{a}[/tex]

So, rewriting the expression we have:

[tex]7^{-32}=\frac{1}{7^{32}}[/tex]

Answer:

[tex](a^m)^n=a^{m*n}[/tex]

[tex]a^{-1}=\frac{1}{a^1}=\frac{1}{a}[/tex]

Answer:(7^-8)^-4=7^(-8)(-4)=7^32

Step-by-step explanation:

D on Edge

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