Question

A rock is thrown vertically upward from ground level at time 0. At time t1 it passes the top of a tall tower, and later, at time t2, it reaches its maximum height. What is the height of the tower? Give your answer in terms of the given variables and g.

Answer 1

Answer:

h = g t₂ t₁ - t₁²

Explanation:

given,

At t = 0 s the rock is at ground level

At t = t₁ rock reaches at the height of the tower

Assuming height of tower be h

At t = t₂ rock is at the highest point.                        

distance of the tower = speed × time

$S = \dfrac{h}{t_1}$                        

at the highest point velocity is zero

using the kinematic equation

v = u +a t                                            

$0 = \dfrac{h}{t_1}-g(t_2-t_1)$

$h = t_1 ( g(t_2-t_1))$

h = g t₂ t₁ - t₁²