Respuesta :
Answer:[tex]1.45 m/s^2[/tex]
Explanation:
weight [tex]=142 lb\approx 64.326 kg[/tex]
Apparent [tex]=121 lb\approx 54.813 kg[/tex]
Apparent weight is decreasing i.e. Elevator is going downward
Apparent weight is given by [tex]m(g-a)=54.813\times 9.81=537.71 N[/tex]
[tex]mg=64.326\times 9.81=631.03 N[/tex]
631.03-ma=537.71
ma=93.32
[tex]a=\frac{93.32}{64.326}[/tex]
[tex]a=1.45 m/s^2[/tex]
Elevator is going downward with acceleration of [tex]1.45 m/s^2[/tex]
The weight in a moving elevator is increased or reduced depending on the direction and magnitude of the elevator's acceleration
The direction and magnitude of the elevator's acceleration are; downwards, 4.758 ft./s²
Reason:
Given parameter are;
Weight of person in the elevator = 142 lb
Apparent weight as the elevator moves = 121 lb
Required:
The direction and magnitude of the elevator's acceleration
Solution:
The sum of forces acting is given by the change in weight as follows;
The apparent weight of the person = m·(g + a) = 121 lb
The weight of the person = m·g = 142 lb
Given that the apparent weight < Actual weight, we write;
The apparent weight of the person = m·(g - a) = 121 lb
- m·(g - a) - m·g = 121 lb - 142 lb = -21 lb
m·(g - a) - m·g = m·a
∴ -m·a = -21 lb
[tex]-a = -\dfrac{21}{m} \ lb[/tex]
[tex]a = \dfrac{21}{m} \ lb[/tex]
[tex]m = \dfrac{142 \, lb}{g}[/tex]
Therefore;
- [tex]a = \dfrac{21 \, lb}{\dfrac{142 \, lb}{g} \ } = \dfrac{21 \, lb}{{142 \, lb}} \times g[/tex]
Acceleration due to gravity, g ≈ 32.1740 ft./s²
- [tex]a = \dfrac{21 \, lb}{{142 \, lb}} \times g = \dfrac{21 \, lb}{{142 \, lb}} \times 31.1740 \, ft./s^2 \approx 4.758 \ ft./s^2[/tex]
Therefore, the magnitude acceleration of the elevator is a ≈ 4.758 ft./s²
Direction of the elevator acceleration vector:
The positive sign of the acceleration of the elevator is the same as the positive sign of gravity acceleration, therefore, the elevator is moving in the direction of gravity, which is downwards
Learn more here:
https://brainly.com/question/20581636
