Question

Which equation represents a line that passes through 4 1/3 and has a slope of 3/4

A. y-3/4 = 1/3 (x-4)
B. y-1/3 = 3/4 (x-4)
C. y-1/3 = 4 (x-3/4)
D. y-4 =3/4 (x-1/3)

Answer 1

Answer:

B

Step-by-step explanation:

equation of a line =

y-y1=m(x-x1)

where m is the gradient and X1 and y1 are the points on the line.

slope= gradient

4=X, 1/3= y

y-1/3 = 3/4 (x-4)

Answer 2

Answer:

B. $y - \frac{1}{3} = \frac{3}{4}(x - 4)$

Step-by-step explanation:

The point-slope form of the equation of a line is

$y - y_1 = m(x - x_1)$

where m = slope, and $(x_1, y_1)$ is a point on the line.

In your case,

m = 3/4, $x_1 = 4$, and $y_1 = \frac{1}{3}$

Substitute the values just above into the equation to get

$y - \frac{1}{3} = \frac{3}{4}(x - 4)$

The answer is B. $y - \frac{1}{3} = \frac{3}{4}(x - 4)$